Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.1 Exercises - Page 755: 8

Answer

$u = v = \lt 15, -3\gt$

Work Step by Step

1. Vector $u$ $u = \lt 11-(-4) , (-4)-(-1) \gt$ $u = \lt 11+4 , (-4)+1 \gt$ $u = \lt 15 , -3 \gt$ 2. Vector $v$ $v = \lt 25-10, 10-13\gt$ $v = \lt 15, -3\gt$ Therefore $u = v = \lt 15, -3\gt$
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