Chapter 11 - Vectors and the Geometry of Space - 11.1 Exercises - Page 755: 28

The terminal point is $( 9 , -6)$

Let $\lt x , y\gt = $ the terminal point $\lt 4 , -9\gt = \lt x-5, y-3\gt$ $4i - 9j = (x-5)i + (y-3)j$ $x$ point: $x-5 = 4$ $x = 4 + 5$ $x = 9$ $y$ point: $y - 3 = -9$ $y = -9 + 3$ $y = -6$ Therefore the terminal point is $( 9 , -6)$