Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.1 Exercises - Page 755: 38

Answer

($\frac{-1.24}{\sqrt{2}},\frac{0.68}{\sqrt{2}}$)

Work Step by Step

Unit vector is of magnitude one by definition. Thus, multiply the equation by: $$ \frac {1}{\sqrt{(6.3)^2+(3.4)^2}}$$
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