Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.1 Exercises - Page 755: 27

Answer

The terminal point is $(3, 5)$

Work Step by Step

Let $\lt x, y \gt = $ terminal point $\lt -1 , 3\gt = \lt x-4, y -2\gt$ $-i+3j = (x-4)i + (y-2)j$ $x$ point: $x-4 = -1$ $x = -1 + 4$ $x = 3$ $y$ point: $y - 2 = 3$ $y = 3 + 2$ $y = 5$ Therefore the terminal point is $(3, 5)$
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