Chapter 10 - Conics, Parametric Equations, and Polar Coordinates - Review Exercises - Page 742: 6

$${\text{graph}}\left( {\text{f}} \right)$$

$$\eqalign{ & {x^2} = 4y \cr & {\text{The equation has the form }}{x^2} = 4py \cr & 4y = 4py \Rightarrow p = 1 \cr & p > 0 \cr & {\text{Therefore,}} \cr & {\text{The parabola opens upward}} \cr & {\text{Graph}}\left( {\text{f}} \right) \cr} $$