Answer
$${\text{Graph }}\left( {\text{e}} \right)$$
Work Step by Step
$$\eqalign{
& 4{x^2} + {y^2} = 4 \cr
& {\text{Divide both sides of the equation by 4}} \cr
& \frac{{4{x^2}}}{4} + \frac{{{y^2}}}{4} = \frac{4}{4} \cr
& \frac{{{x^2}}}{1} + \frac{{{y^2}}}{4} = 1 \cr
& {\text{The equation has the standard form}} \cr
& \frac{{{x^2}}}{{{b^2}}} + \frac{{{y^2}}}{{{a^2}}} = 1,{\text{ }}a > b \cr
& \frac{{{x^2}}}{1} + \frac{{{y^2}}}{4} = 1 \Rightarrow a = 2,b = 1 \cr
& {\text{With}} \cr
& {\text{Vertex }}\left( {0, - a} \right){\text{ and }}\left( {0,a} \right) \Rightarrow \left( {0, - 2} \right){\text{ and }}\left( {0,2} \right) \cr
& {\text{Graph }}\left( {\text{e}} \right) \cr} $$
