Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 10 - Conics, Parametric Equations, and Polar Coordinates - Review Exercises - Page 742: 4

Answer

$${\text{Graph}}\left( {\text{d}} \right)$$

Work Step by Step

$$\eqalign{ & {y^2} - 4{x^2} = 4 \cr & {\text{Divide both sides by 4}} \cr & \frac{{{y^2}}}{4} - \frac{{4{x^2}}}{4} = \frac{4}{4} \cr & \frac{{{y^2}}}{4} - {x^2} = 1 \cr & {\text{This equation is in standard form}} \cr & \frac{{{y^2}}}{{{a^2}}} - \frac{{{x^2}}}{{{b^2}}} = 1 \cr & {\text{Therefore,}} \cr & \underbrace {\frac{{{y^2}}}{4} - {x^2} = 1 \Rightarrow \frac{{{y^2}}}{{{2^2}}} - {x^2} = 1}_ \Downarrow \cr & \boxed{a = 2},\boxed{b = 1} \cr & {\text{Characteristics of the hyperbola }} \cr & {\text{Orientation}}:{\text{ Vertical transverse axis}} \cr & {\text{Center}}\left( {0,0} \right) \cr & \underbrace {{\text{Vertices}}\left( {0, - 2} \right){\text{ and }}\left( {0,2} \right)}_ \Downarrow \cr & {\text{Vertices}}\left( {0, - 2} \right){\text{ and }}\left( {0,2} \right),{\text{ so}} \cr & {\text{Graph}}\left( {\text{d}} \right) \cr} $$
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