Answer
$${\text{Graph }}\left( {\text{a}} \right)$$
Work Step by Step
$$\eqalign{
& {x^2} + 4{y^2} = 4 \cr
& {\text{Divide both sides by 4}} \cr
& \frac{{{x^2}}}{4} + \frac{{4{y^2}}}{4} = \frac{4}{4} \cr
& \frac{{{x^2}}}{4} + {y^2} = 1 \cr
& {\text{The equation is in standard form}} \cr
& \frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1 \cr
& \frac{{{x^2}}}{4} + {y^2} = 1 \Rightarrow a = 2,b = 1 \cr
& {\text{With}} \cr
& {\text{Vertex }}\left( { - a,0} \right){\text{ and }}\left( {a,0} \right) \Rightarrow \left( { - 2,0} \right){\text{ and }}\left( {2,0} \right) \cr
& {\text{Therefore,}} \cr
& {\text{Graph }}\left( {\text{a}} \right) \cr} $$
