Answer
$\lim\limits_{x\to5^+}\dfrac{x-5}{x^2-25}=\dfrac{1}{10}.$
Work Step by Step
$\lim\limits_{x\to5^+}\dfrac{x-5}{x^2-25}=\lim\limits_{x\to5^+}\dfrac{x-5}{(x-5)(x+5)}$
$=\lim\limits_{x\to5^+}\dfrac{1}{x+5}=\dfrac{1}{5+5}=\dfrac{1}{10}.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.4 Exercises - Page 79: 9
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
