Answer
A vertical asymptote at $x=0.$
This discontinuity is not removable.
Work Step by Step
The only restriction on the domain is that $x$ cannot be equal to $0.$
$\lim\limits_{x\to0^-}=-\infty$ and $\lim\limits_{x\to0^+}=+\infty$ hence there is a vertical asymptote at $x=0.$
Vertical asymptotes are not removable.
