Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.4 Exercises - Page 79: 19

Answer

$\lim\limits_{x\to1}f(x)=2.$

Work Step by Step

$\lim\limits_{x\to1^-}f(x)=\lim\limits_{x\to1^-}(x^3+1)=(1^-)^3+1=2.$ $\lim\limits_{x\to1^+}f(x)=\lim\limits_{x\to1^+}(x+1)=(1^++1)=2.$ Since $\lim\limits_{x\to1^-}f(x)=\lim\limits_{x\to1^+}f(x)=2\to \lim\limits_{x\to1}f(x)=2.$
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