Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.4 Exercises: 7



Work Step by Step

Using direct substitution: $\lim\limits_{x\to8^+}\dfrac{1}{x+8}=\dfrac{1}{8+8}=\dfrac{1}{16}.$
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