## Calculus, 10th Edition (Anton)

$x=\frac{1}{3}\ln(\frac{7}{2})$
Divide each side of the equation by 2, leaving $e^{3x}=\frac{7}{2}$. Take the natural logarithm of each side to get $ln(e^{3x})=ln(\frac{7}{2})$, which simplifies to $3x=ln(\frac{7}{2})$ after using the log rule $\log(a^b)=b \times \log(a)$. Dividing each side by three leaves $x=\frac{1}{3}\ln(\frac{7}{2})$.