## Calculus, 10th Edition (Anton)

$x=-\frac{1}{2}\ln(\frac{5}{3})$
Divide each side by $3$ to get $e^{-2x}=\frac{5}{3}$. Take the natural logarithm of each side to get $ln(e^{-2x})=ln(\frac{5}{3})$, or $-2x=ln(\frac{5}{3})$. Dividing each side by $-2$ gives $x=-\frac{1}{2}\ln(\frac{5}{3})$.