Answer
$A=\dfrac{65}{4} $
Work Step by Step
$f(x) = x^3$ $ [2,3] $
$A =\int_2^3 x^3 dx $
$A = [\frac{x^4}{4}]^3_2 $
$A = [(\frac{3^4}{4})-(\frac{2^4}{4})] $
$A = [\frac{81}{4} - \frac{16}{4}] $
$A = \dfrac{65}{4} $
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 4 - Integration - 4.6 The Fundamental Theorem Of Calculus - Exercises Set 4.6 - Page 320: 5
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