Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.9 Local Linear Approximation; Differentials - Exercises Set 2.9 - Page 181: 20

Answer

$7.64$

Work Step by Step

The expression for $y$ can be written as: $y=x^3$ Now, $\dfrac{dy}{dx}=3x^2$ $dy=3x^2 dx$ Next, we have: $dy=3\times (2)^2(-0.03)=-0.36$ So, the new $y$ value is equal to $-0.36+2^3=7.64$
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