Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.3 Introduction To Techniques Of Differentiation - Exercises Set 2.3 - Page 140: 15



Work Step by Step

$f(x)=(3x^{2}+1)^{2}=9x^{4}+6x^{2}+1$ $f'(x)=9(4)x^{4-1}+6(2)x^{2-1}$ $f'(x)=9(4)x^{4-1}+6(2)x^{2-1}$ $f'(x)=36x^{3}+12x$ $f'(x)=12x(3x^{2}+1)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.