Answer
$f'(x)=24x^{-9}+\frac{1}{\sqrt x}$
Work Step by Step
$f(x)=-3x^{-8}+2\sqrt x=-3x^{-8}+2x^{\frac{1}{2}}$
Calculate the first derivative:
$f'(x) =-3(-8)x^{-8-1}+2\left(\frac{1}{2}\right)x^{\frac{1}{2}-1}$
$f'(x) =24x^{-9}+x^{-\frac{1}{2}}$
$f'(x)=24x^{-9}+\frac{1}{\sqrt x}$