Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.3 Introduction To Techniques Of Differentiation - Exercises Set 2.3 - Page 140: 11

Answer

$f'(x)=24x^{-9}+\frac{1}{\sqrt x}$

Work Step by Step

$f(x)=-3x^{-8}+2\sqrt x=-3x^{-8}+2x^{\frac{1}{2}}$ $f'(x) =-3(-8)x^{-8-1}+2(\frac{1}{2})x^{\frac{1}{2}-1}$ $f'(x) =24x^{-9}+x^{-\frac{1}{2}}$ $f'(x)=24x^{-9}+\frac{1}{\sqrt x}$
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