Answer
$\frac{dx}{dt}=2t-1$
Work Step by Step
$x=t^{2}-t$
$\frac{dx}{dt}=2t^{2-1}-1t^{1-1}$
$\frac{dx}{dt}=2t^{1}-1t^{0}$
$\frac{dx}{dt}=2t-1$
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