Answer
$\frac{d}{dα}[2α^{-1}+α]=-2α^{-2}+1$
Work Step by Step
$\frac{d}{dα}[2α^{-1}+α]=2(-1)α^{-2}+1$
$\frac{d}{dα}[2α^{-1}+α]=-2α^{-2}+1$
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