Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 14 - Multiple Integrals - 14.2 Double Integrals Over Nonrectangular Regions - Exercises Set 14.2 - Page 1017: 41

Answer

$$170$$

Work Step by Step

Volume under the function $f(x, y)=z$ and above the region $R$ is given by \[ \begin{array}{c} \iint_{R} f(x, y) d A=V \\ \iint_{R} y^{2}+9 x^{2} d A=V \\ =\int_{0}^{3} \int_{0}^{2} 9 x^{2}+y^{2} d y d x \\ =\int_{0}^{3}\left[9 y x^{2} +\frac{y^{3}}{3}\right]_{0}^{2} d x \\ =\int_{0}^{3} \frac{8}{3}+ 18 x^{2} d x \end{array} \] $$=[\frac{8 x}{3}+6 x^{3} ]_{0}^{3}$$ \[ 170=\frac{8 \cdot 3}{3}+6 \cdot 3^{3} \]
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.