Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 13 - Partial Derivatives - 13.3 Partial Derivatives - Exercises Set 13.3 - Page 937: 48

Answer

$$\frac{{\partial w}}{{\partial x}} = \frac{{2x}}{{{y^2} + {z^2}}}$$ $$\frac{{\partial w}}{{\partial y}} = \frac{{ - 2y\left( {{z^2} + {x^2}} \right)}}{{{{\left( {{y^2} + {z^2}} \right)}^2}}}$$ $$\frac{{\partial w}}{{\partial z}} = \frac{{2z\left( {{y^2} - {x^2}} \right)}}{{{{\left( {{y^2} + {z^2}} \right)}^2}}}$$

Work Step by Step

$$\eqalign{ & w = \frac{{{x^2} - {y^2}}}{{{y^2} + {z^2}}} \cr & {\text{Calculate }}\frac{{\partial w}}{{\partial x}} \cr & \frac{{\partial w}}{{\partial x}} = \frac{\partial }{{\partial x}}\left[ {\frac{{{x^2} - {y^2}}}{{{y^2} + {z^2}}}} \right] \cr & \frac{{\partial w}}{{\partial x}} = \frac{\partial }{{\partial x}}\left[ {\frac{{{x^2}}}{{{y^2} + {z^2}}}} \right] - \frac{\partial }{{\partial x}}\left[ {\frac{{{y^2}}}{{{y^2} + {z^2}}}} \right] \cr & \frac{{\partial w}}{{\partial x}} = \frac{1}{{{y^2} + {z^2}}}\frac{\partial }{{\partial x}}\left[ {{x^2}} \right] \cr & \frac{{\partial w}}{{\partial x}} = \frac{{2x}}{{{y^2} + {z^2}}} \cr & \cr & {\text{Calculate }}\frac{{\partial w}}{{\partial y}} \cr & \frac{{\partial w}}{{\partial y}} = \frac{\partial }{{\partial y}}\left[ {\frac{{{x^2} - {y^2}}}{{{y^2} + {z^2}}}} \right] \cr & {\text{use quotient rule}} \cr & \frac{{\partial w}}{{\partial y}} = \frac{{\left( {{y^2} + {z^2}} \right)\left( { - 2y} \right) - \left( {{x^2} - {y^2}} \right)\left( {2y} \right)}}{{{{\left( {{y^2} + {z^2}} \right)}^2}}} \cr & \frac{{\partial w}}{{\partial y}} = \frac{{ - 2{y^3} - 2y{z^2} - 2{x^2}y + 2{y^3}}}{{{{\left( {{y^2} + {z^2}} \right)}^2}}} \cr & \frac{{\partial w}}{{\partial y}} = \frac{{ - 2y{z^2} - 2{x^2}y}}{{{{\left( {{y^2} + {z^2}} \right)}^2}}} \cr & \frac{{\partial w}}{{\partial y}} = \frac{{ - 2y\left( {{z^2} + {x^2}} \right)}}{{{{\left( {{y^2} + {z^2}} \right)}^2}}} \cr & \cr & {\text{Calculate }}\frac{{\partial w}}{{\partial z}} \cr & \frac{{\partial w}}{{\partial z}} = \frac{\partial }{{\partial z}}\left[ {\frac{{{x^2} - {y^2}}}{{{y^2} + {z^2}}}} \right] \cr & \frac{{\partial w}}{{\partial z}} = \left( {{x^2} - {y^2}} \right)\frac{\partial }{{\partial z}}\left[ {{{\left( {{y^2} + {z^2}} \right)}^{ - 1}}} \right] \cr & \frac{{\partial w}}{{\partial z}} = - \left( {{x^2} - {y^2}} \right){\left( {{y^2} + {z^2}} \right)^{ - 2}}\frac{\partial }{{\partial z}}\left[ {{y^2} + {z^2}} \right] \cr & \frac{{\partial w}}{{\partial z}} = - 2z\left( {{x^2} - {y^2}} \right){\left( {{y^2} + {z^2}} \right)^{ - 2}} \cr & \frac{{\partial w}}{{\partial z}} = \frac{{2z\left( {{y^2} - {x^2}} \right)}}{{{{\left( {{y^2} + {z^2}} \right)}^2}}} \cr} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.