Answer
$z_x=ye^{xy}sin(4y^2)$
$z_y=8ye^{xy}cos(4y^2)+xe^{xy}sin(4y^2)$
Work Step by Step
Take the first partial derivatives of the given function. When taking partial derivative with respect to x, treat y as a constant, and vice versa:
$z_x=e^{xy}sin(4y^2)*y=ye^{xy}sin(4y^2)$
$z_y=e^{xy}*cos(4y^2)*8y+e^{xy}sin(4y^2)*x=8ye^{xy}cos(4y^2)+xe^{xy}sin(4y^2)$