Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 12 - Vector-Valued Functions - 12.5 Curvature - Exercises Set 12.5 - Page 879: 28

Answer

$$\frac{36}{89 \sqrt{89}}$$

Work Step by Step

By implicit differentiation: $0=-8 x+(d y / d x)2 y$ $4 x / y=\frac{d y}{d x}$ $\frac{d^{2} y}{d x^{2}}=4 \cdot \frac{1 \cdot y-(d y / d x) \cdot x}{y^{2}}=4 \cdot \frac{y-(4 x / y) \cdot x}{y^{2}}=4 \cdot \frac{-4 x^{2}}{y^{3}+y^{2}}=\frac{36}{y^{3}}$ $\frac{36 /|y|^{3}}{\left(16 x^{2} / y^{2}+1\right)^{3 / 2}}=\kappa$ for $(x, y)=(2,5) \quad \kappa=\frac{36 / 125}{(64 / 25+1)^{3 / 2}}=\frac{36}{89 \sqrt{89}}$
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