Chapter 12 - Vector-Valued Functions - 12.5 Curvature - Exercises Set 12.5 - Page 879: 19

True

Step 1 This statement is true because, as proved in Example 1, the circle has a constant curvature: \[ k = \frac{1}{a} \] where $a$ is the radius of the circle. If a circle has a radius $a = 2$, its curvature is: \[ k = \frac{1}{2} \] Result: True