Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 12 - Vector-Valued Functions - 12.1 Introduction To Vector-Valued Functions - Exercises Set 12.1 - Page 846: 7

Answer

$x(t) = 3t^2, \quad y(t) = -2$

Work Step by Step

Step 1 Given: \[ \mathbf{r}(t) = 3t^2\mathbf{i} - 2\mathbf{j} \] Step 2 Since the vector equation of the curve given by: \[ \mathbf{r}(t) = x(t)\mathbf{i} + y(t)\mathbf{j} \] is: \[ \mathbf{r}(t) = 3t^2\mathbf{i} - 2\mathbf{j} \] then the corresponding parametric equations to the given vector equation are: \[ x(t) = 3t^2, \quad y(t) = -2 \] Result \[ x(t) = 3t^2, \quad y(t) = -2 \]
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