Answer
Discontinuities at $x = \frac{\pi}{2} + k \pi$, where $k$ is an integer.
Work Step by Step
Discontinuities exist in $f(x) = \sqrt{2+tan^2(x)}$ where $tan(x)$ is undefined or where $2+tan^2(x)<0$.
$tan(x)$ is undefined at $x = \frac{\pi}{2} + k \pi$, where $k$ is an integer.
Solving for $x$ where $2+tan^2(x)<0$, we find
$$2+tan^2(x)<0$$
$$x = \frac{\pi}{2} + k \pi$$