Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 1 - Limits and Continuity - 1.6 Continuity of Trigonometric Functions - Exercises Set 1.6 - Page 105: 15


$$-3 $$

Work Step by Step

Given $$\lim_{x\to 0}\frac{x^2-3\sin x}{x}$$ Then \begin{align*} \lim_{x\to 0}\frac{x^2-3\sin x}{x}&=\lim_{x\to 0}\frac{x^2 }{x} -3\lim_{x\to 0}\frac{ \sin x}{x} \\ &=0-3(1)\\ &=-3 \end{align*}
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