Answer
$$\frac{1}{2}$$
Work Step by Step
Given $$\lim_{h\to 0}\frac{\sin h}{2h}$$
Then
\begin{align*}
\lim_{h\to 0}\frac{\sin h}{2h}&=\frac{1}{2}\lim_{h\to 0}\frac{\sin h}{ h}\\
&=\frac{1}{2}
\end{align*}
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 1 - Limits and Continuity - 1.6 Continuity of Trigonometric Functions - Exercises Set 1.6 - Page 105: 14
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
