Answer
$$y'=e^{x+1}$$
Work Step by Step
$$y=e^{x+1}+1$$
$$y=e^x\times e+1$$
So, the derivative of $y$ is $$y'=e\frac{d}{dx}(e^x)+\frac{d}{dx}(1)$$ (since $e$ is a number) $$y'=e\times(e^x)+0$$
$$y'=e^{x+1}$$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 3 - Section 3.1 - Derivatives of Polynomials and Exponential Functions - 3.1 Exercises - Page 182: 34
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