Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 14 - Section 14.3 - Partial Derivatives - 14.3 Exercise - Page 970: 67

Answer

$f_{xzy} = 6yz^2$

Work Step by Step

Since $f_{xzy} = f_{yzx}$, then $f_{y} = 2xyz^{3}$, $f_{yz} = 6yxz^2$, $f_{yzx} = 6yz^2$ Therefore, $f_{xzy} = 6yz^2$
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