Answer
$w_x=\frac{1}{x+2y+3z}$, $w_y=\frac{2}{x+2y+3z}$, $w_z=\frac{3}{x+2y+3z}$.
Work Step by Step
$w=\ln{(x+2y+3z)}$
In order to find $w_x$ we treat $y$ and $z$ as constants and differentiate with respect to $x$.
$w_x=\frac{1}{x+2y+3z}$
Analogously.
$w_y=\frac{2}{x+2y+3z}$
$w_z=\frac{3}{x+2y+3z}$
