Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 14 - Section 14.3 - Partial Derivatives - 14.3 Exercise - Page 970: 37

Answer

$R_t(0,1)=1$.

Work Step by Step

$R(s,t)=te^\frac{s}{t}$ $R_t(s,t)=e^\frac{s}{t}-\frac{se^\frac{s}{t}}{t}\Rightarrow R_t(0,1)=e^\frac{(0)}{(1)}-\frac{(0)e^\frac{(0)}{(1)}}{(1)}=1$
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