Answer
a) $g(3,1)=9\ln 4$
b) Domain: $\{(x,y)|x+y>0\}$
See graph in image
c) Range: negative infinity to positive infinity.
Work Step by Step
a) $g(3,1)=3^2\ln(3+1)=9\ln 4$
b) Domain: $\{(x,y)|x+y>0\}$
See graph in image
c) The range of $x^2$ is greater than or equal to 0 but because it is multiplied by the logarithmic function, it is all values from negative infinity to positive infinity.
