Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 14 - Section 14.1 - Functions of Several Variables - 14.1 Exercise - Page 946: 13

Answer

$D=\{(x,y)\in\mathbb{R}^2|xy\ge0, x\ne-1\}$

Work Step by Step

The denominator cannot be equal to 0. Therefore, $x\ne-1$. Moreover, the values under the square root must be greater than or equal to 0, which means $xy\ge0$. $D=\{(x,y)\in\mathbb{R}^2|xy\ge0, x\ne-1\}$
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