Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 14 - Section 14.1 - Functions of Several Variables - 14.1 Exercise - Page 946: 12

Answer

$D=\{(x,y)\in\mathbb{R}^2| x^2+y^2\ne1, x<2\}$

Work Step by Step

The denominator cannot be equal to 0. Therefore, $x^2+y^2\ne1$, which means the values on the circle with center at the origin and radius 1. Moreover, the value inside the logarithm must be greater than 0. Therefore, $2>x$. Thus, $D=\{(x,y)\in\mathbb{R}^2| x^2+y^2\ne1, x<2\}$
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