Answer
$(y+1)^2=\frac{1}{2}(x-3)$
Work Step by Step
Parabola passing through $(-15,2)$
Put $x=-15$ and $y=2$
Therefore,
$(2+1)^2=4p(-15-3)$
$p=-\frac{1}{8}$
Thus,
$(y+1)^2=\frac{1}{2}(x-3)$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 709: 37
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