Answer
$(x-2)^2=-16(y-3)$
Work Step by Step
Distance of the point $(x,y)$ from the line $y=7$ is $|y-7|$
Therefore, the equation of the parabola is
$|y-7|=\sqrt {(x-2)^2+(y+1)^{2}}$
$x^2-4x+4=-16y+48$
$(x-2)^2=-16(y-3)$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 10 - Section 10.5 - Conic Sections - 10.5 Exercises - Page 709: 36
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