Answer
One common solution $\Rightarrow$ $(0,-3)$
Work Step by Step
We use the addition method below:
We add the 2 equations:
$5x-2y=6$
$3x-4y=12$
Multiply both sides of the 1st equation by $-2$ to cancel $y$.
$-10x+4y=-12$
$\underline{+3x-4y=12}$
$-7x=0$
Solve for $x$:
$x=\frac{0}{-7}=0$
Substitute into any of the 2 equations and solve for $y$:
$5x-2y=6$
$5(0)-2y=6$
$-2y=6$
$y=\frac{6}{-2}$
$y=-3$
