Answer
One common solution $\Rightarrow$ $(0,3)$
Work Step by Step
We use the addition method below:
We add the two equations:
$8x+12y=36$
$16x+15y=45$
Multiply both sides of the first equation by $-2$ to cancel $x$.
$-16x-24y=-72$
$\underline{+16x+15y=+45}$
$-9y=-27$
Solve for $y$:
$y=\frac{-27}{-9}=3$
Substitute into any of the two equations and solve for $x$:
$8x+12y=36$
$8x+12(3)=36$
$8x+36=36$
$8x=36-36$
$8x=0$
$x=\frac{0}{8}$
$x=0$
