Answer
One common solution $\Rightarrow$ $(-\frac{1}{3},2)$
Work Step by Step
We use the addition method below:
We add the two equations:
$-3x+2y=5$
$-30x+y=12$
Multiply both sides of the first equation by $-10$ to cancel $x$.
$+30x-20y=-50$
$\underline{-30x+y=12}$
$-19y=-38$
Solve for $y$:
$y=\frac{-38}{-19}=2$
Substitute into any of the two equations and solve for $x$:
$-3x+2y=5$
$-3x+2(2)=5$
$-3x+4=5$
$-3x=5-4$
$-3x=1$
$x=\frac{1}{-3}=-\frac{1}{3}$
