## Elementary Technical Mathematics

Use standard conversion factors to restate the ratio in the requested units of measure. Reduce fractions to express in lowest terms. $\frac{750mL}{5hr}=\frac{750mL}{5hr}\times\frac{1hr}{60min}=\frac{750mL}{300min}=\frac{750\div150\ mL}{300\div150\ min}=\frac{5\ mL}{2\ min}$ Restate the improper fraction as a mixed number. $\frac{5\ mL}{2\ min}=2.5\ mL/min$