Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 7 - Section 7.1 - Ratio - Exercises - Page 271: 59


1 cougar per 150 $mi^2$

Work Step by Step

First find the actual amount of land by subtracting out the area covered in water. living area = $45000\ mi^2-3000\ mi^2=42000\ mi^2$ Next find the ratio and reduce to lowest terms. $\frac{280\ cougars}{42000\ mi^2}=\frac{280\div280\ cougars}{42000\div280\ mi^2}=\frac{1\ cougar}{150\ mi^2}$
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