## Elementary Technical Mathematics

Use standard conversion factors to restate the ratio in the requested units of measure. Reduce fractions to express in lowest terms. $\frac{1200mL}{5hr}=\frac{1200mL}{5hr}\times\frac{1hr}{60min}=\frac{1200mL}{300min}=\frac{1200\div300\ mL}{300\div300\ min}=\frac{4mL}{1min}$