Answer
$4y^3-3y-\frac{2}{y}.$
Work Step by Step
We divide each term of the polynomial by the monomial as follows
$$
\frac{24y^5 - 18y^3 - 12y}{6y^2 }= \frac{24y^5 }{6y^2 }+ \frac{ - 18y^3 }{6y^2 }+ \frac{ - 12y}{6y^2 } \\
=4y^3-3y-\frac{2}{y}.
$$
