Answer
$\frac{ 4x^2z^4}{ 9y}$
Work Step by Step
We divide by the monomial as follows
$$
(-72x^3yz^4) \div (-162xy^2)=\frac{-72x^3yz^4}{-162xy^2}\\=\frac{-18\cdot4x^3yz^4}{-18\cdot 9xy^2}
=\frac{ 4x^2z^4}{ 9y}
.$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 5 - Section 5.6 - Division by a Monomial - Exercise - Page 227: 29
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