Answer
$$=\frac{5 b^2}{ 9c^2}
.$$
Work Step by Step
We divide by the monomial as follows
$$
\frac{35a^3b^4c^6}{63a^3b^2c^8}=\frac{5\cdot 7a^3b^4c^6}{7\cdot 9a^3b^2c^8}=\frac{5 b^2}{ 9c^2}
.$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 5 - Section 5.6 - Division by a Monomial - Exercise - Page 227: 28
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