Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 5 - Section 5.6 - Division by a Monomial - Exercise - Page 227: 42

Answer

$-a^3+8a^2-2a+3.$

Work Step by Step

We divide each term of the polynomial by the monomial as follows $$ \frac{4a^5 - 32a^4 + 8a^3 - 12a^2}{-4a^2 }= \frac{4a^5 }{-4a^2 }+\frac{ - 32a^4 }{-4a^2 }+\frac{ 8a^3 }{-4a^2 }+\frac{ - 12a^2}{-4a^2 }\\ =-a^3+8a^2-2a+3. $$
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