## Elementary Technical Mathematics

$$A=82.9°$$ $$B=7.1°$$
Find angle A. We can use the trigonometric function for tangent to find angle A. $tan A=\frac{a}{b}$ $tan A=\frac{847m}{105m}$ $tan A=8.0667$ Now we solve for A by multiplying both sides of the equation by the inverse tangent. So, $tan^{-1}(tan A) = tan^{-1}(8.0667)$ $A = tan^{-1}(8.0667)$ $A=82.9°$ Find angle B. We know that in right triangles the sum of the acute angles is 90°. So, $A+B=90°$ Solving for $B$, we get $B=90°-A$ $B=90°-82.9°$ $B=7.1°$