Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 13 - Section 13.2 - Using Trigonometric Ratios to Find Angles - Exercise - Page 546: 20


$$A=54.9°$$ $$B=35.1°$$

Work Step by Step

Find angle A. We can use the trigonometric function for sine to find angle A. $sin A=\frac{a}{c}$ $sin A=\frac{48.7cm}{59.5cm}$ $sin A=0.8185$ Now we solve for A by multiplying both sides of the equation by the inverse sine. So, $sin^{-1}(sin A) = sin^{-1}(0.8185)$ $A = sin^{-1}(0.8185)$ $A=54.9°$ Find angle B. We know that in right triangles the sum of the acute angles is 90°. So, $A+B=90°$ Solving for $B$, we get $B=90°-A$ $B=90°-54.9°$ $B=35.1°$
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